find the perimeter of triangle formed by points(5,0),(0,12)and (0,0)
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0
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write question properly it is point or comaa
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5
Step-by-step explanation:
- so (A) 5,0 (B)0,12 (C) (0,0) By using distance formula A= √(5(2) - 0)= (5×5 -0) =√25-0 = √25= 5 ,B= √( 0- 122) =√(0-12×12)= √144 -0= √144 = 12 and C =√0-0= 0. so Perimeter= A+B+C = 5+12+0= 17 . so answer is 17 plz mark as branliest
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