Question

find the perimeter of triangle formed by the points (0, 0), (2, 0) and
(0, 2).

Answer 1

Answer:

4+2sqrt (2)

Step-by-step explanation:

hope this helps you

Answer 2

Given:

Points of a triangle = A(0 ,0), B(2, 0), C(0, 2)

To find:

The perimeter of the triangle

Solution:

Perimeter of a triangle is the sum of all the sides of the triangle.

We can find the sides of the triangle by calculating the distance between the points.

Distance between two points P$(x_1, y_1)$ and $(x_2,y_2)$ is given by

$PQ=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

So,

AB=$\sqrt{(0-2)^2+(0-0)^2} =\sqrt{4}$

=2units

BC=$\sqrt{(2-0)^2+(0-2)^2}=\sqrt{4+4}$

=$\sqrt{8}=2\sqrt{2}$units

AC=$\sqrt{(0-0)^2+(0-2)^2} =\sqrt{4}$

=2units

Therefore, perimeter =AB+BC+AC

∴Perimeter=$2+2\sqrt{2}+2$

$=4+2\sqrt{2}$sq.units

Hence, the perimeter of the triangle formed by the given points is $4+2\sqrt{2}$sq.units.