Math, asked by mubeekhan007, 3 months ago

Find the perimeter of triangle if its sides are 3x-2y +1 , 2x +y -3 and x+y+1.​

Answers

Answered by SattwikRay
0

Answer:

Given sides of a triangle:

Side 1 = 3x - 2y + 1

Side 2 = 2x + y - 3

Side 3 = x  + y + 1

Perimeter of the triangle = Side 1 + Side 2 + Side 3

⇒ 3x - 2y + 1 + 2x + y - 3 + x + y + 1

Now, we can group the like terms and add them together.

⇒ (3x + 2x + x) + (y + y - 2y) + (1 + 1 - 3)

⇒ 6x + 0 + (-1)

⇒ 6x - 1

∴ Hence, the perimeter of the rectangle is 6x - 1.

Thnx and have a nice day!

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