Find the perimeter of triangle if its sides are 3x-2y +1 , 2x +y -3 and x+y+1.
Answers
Answered by
0
Answer:
Given sides of a triangle:
Side 1 = 3x - 2y + 1
Side 2 = 2x + y - 3
Side 3 = x + y + 1
Perimeter of the triangle = Side 1 + Side 2 + Side 3
⇒ 3x - 2y + 1 + 2x + y - 3 + x + y + 1
Now, we can group the like terms and add them together.
⇒ (3x + 2x + x) + (y + y - 2y) + (1 + 1 - 3)
⇒ 6x + 0 + (-1)
⇒ 6x - 1
∴ Hence, the perimeter of the rectangle is 6x - 1.
Thnx and have a nice day!
✌(●'◡'●)
Similar questions