find the perimeter of triangle is 7x^2-17xy+15y^2+8 and two sides are 3x^2-6xy+4y^2-5 and 2x^2-9xy+6y^2+6.find the third sides of the triangle
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Answer:
2x^2-2xy+5y^2+7
Step-by-step explanation:
perimeter of a triangle is sum of all sides
7x^2_17xy+15y^2+8=3x^2-6xy+4y^2-5+2x^2-9xy+6y^2+6+t
t denotes the third sides of triangle
t=2x^2-2xy+5y^2+7
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