find the perimeter of triangle whose side (3x+2y-4z)
units,(2x-y tz) units and
(2x-y+z)
Answers
Answered by
1
Answer:
Group like terms.
3x+2x+2x=7x
+2y-y-y=0
-4z+z=-3z
7x-3z+tz
Answered by
2
Answer:
perimeter= sum of all sides
= 3x+2y+4z+2x-y+z+2x-y+z
= 7x+0y+6z
= 7x+6z
Hope this helps...
Similar questions