Question

find the perimeter of triangle whose side are 2a+3b,b-a,4a-2b

Answer 1

perimeter of triangle= (2a+3b)+(b-a)+(4a-2b)
=2a+3b+b-a+4a-2b
=5a+2b

Answer 2

The perimeter of triangle whose side are 2a + 3b , b - a , 4a - 2b is 5a + 2b

Given :

The sides of a triangle are 2a + 3b , b - a , 4a - 2b

To find :

The perimeter of the triangle

Solution :

Step 1 of 2 :

Write down the given sides of the triangle

Here it is given that sides of the triangle are 2a + 3b , b - a , 4a - 2b

Step 2 of 2 :

Find perimeter of the triangle

The perimeter of the triangle

= Sum of the sides of the triangle

= ( 2a + 3b ) +( b - a ) + ( 4a - 2b )

= 2a + 3b + b - a + 4a - 2b

= 2a - a + 4a + 3b + b - 2b

= 5a + 2b

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