Find the perimeter of triangle whose vertices are (0,4), (0,0), (3,0)
Answers
Answered by
8
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
Refer to attachment
⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️
...Hope it helps....
Attachments:
Answered by
2
use distance formula,
AB =√(4²+0) =4
BC= √(0+3²) = 3
CA =√(4²+3²) =5
now ,
perimeter of ∆ = 3 + 4 + 5= 12 unit
Similar questions