Math, asked by aashikhokhani, 3 months ago

Find the perimeter of triangle with sides
2x² + 2xy +3, 2x² - xy - I and xy - x² + 2​

Answers

Answered by saifalam5942
2

Perimeter of a rectangle is 2(L+B)

Given, two adjacent sides are 5x

2

+2xy−13,2x

2

−6xy+11

Therefore,

2(L+B)

=2(5x

2

+2xy−13+2x

2

−6xy+11)

=2(7x

2

−4xy−2)

=14x

2

−8xy−4

Answered by anandswaroop8
1
Perimeter = sum of all sides
= 2x2+2xy+3+2x2-xy-1+xy-x2+2
=4x^2+2xy+4
I hope this was the answer you were looking for :)
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