Find the perimeter of triangle with sides
2x² + 2xy +3, 2x² - xy - I and xy - x² + 2
Answers
Answered by
2
Perimeter of a rectangle is 2(L+B)
Given, two adjacent sides are 5x
2
+2xy−13,2x
2
−6xy+11
Therefore,
2(L+B)
=2(5x
2
+2xy−13+2x
2
−6xy+11)
=2(7x
2
−4xy−2)
=14x
2
−8xy−4
Answered by
1
Perimeter = sum of all sides
= 2x2+2xy+3+2x2-xy-1+xy-x2+2
=4x^2+2xy+4
I hope this was the answer you were looking for :)
= 2x2+2xy+3+2x2-xy-1+xy-x2+2
=4x^2+2xy+4
I hope this was the answer you were looking for :)
Similar questions