Question

find the perimeter ofrectangle whose length is 40 cm and a diagonal is 41 cm​

Answer 1

Answer:

98 cm

Step-by-step explanation:

let ABCD be rectangle.

Then AC will be diagonal. And angle B = 90.

Length(BC) = 40 cm

diagonal(AB) = 41 cm

By using pythagoras theorem, we have:-

AB^{2} + BC^{2} = AC^{2}AB

2

+BC

2

=AC

2

x^{2} + 40^{2} = 41^{2}x

2

+40

2

=41

2

AB^{2} = 41^{2} - 40^{2}AB

2

=41

2

−40

2

AB^{2} = 1681 - 1600 = 81AB

2

=1681−1600=81

AB = \sqrt{81} = 9 cmAB=

81

=9cm

Now, Perimeter of rectangle = 2(L+B) = 2(BC+ AB)

= 2(9 + 40) = 2(49)

= 98 cm

Answer 2

Answer:

98 cm

Step-by-step explanation:

As we can see in the rectangle,

Now as given in the question,

Diagonal = 41 cm.

Length = 40 cm.

So, Putting these value we get,

Hence the width of the rectangle is 9 cm.

So 

The perimeter of the rectangle = 2 ( Length + Width )

                                                 = 2 ( 40 cm + 9 cm )

                                                 = 2 x 49 cm

                                                 = 98 cm 

Hence the perimeter of the rectangle is 98 cm.

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thanks alott