Question

find the perimeter (P = 2L + 2w)

A rectangle is (y + 2) m long and (5y – 1) m wide

Much appreciated with solution thanks :D​

Answer 1

Answer:

P=12y+2

Step-by-step explanation:

To solve this problem, lets first look at the information we are given.

L=(y + 2)

w=(5y – 1)

P = 2L + 2w

Next, lets plug in our L and w into our equation to find the perimeter.

P = 2L + 2w

P = 2(y + 2) + 2(5y-1)

Now, solve for P.

P = 2(y + 2) + 2(5y-1)

P=2y+4+10y-2

P=12y+2

So, P=12y+2. If you then figured out the value of y, you could plug it into the equation to find the real perimeter, but, for now, all we know is that P=12y+2.

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