Find the perimeter
perimeter of the triangle where
are 2x + 3y +3z, 4x - 4y + 2z
and
6x + y -2z
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Answer:
Sides of the triangle are: 2x + 3y + 3z ; 4x - 4y + 2z ; 6x + y -2z
We know that the perimeter of a triangle is equal to sum of all its sides
Therefore perimeter = 2x + 3y + 3z + (4x - 4y + 2z) + (6x + y -2z)
= 2x + 3y + 3z + 4x - 4y + 2z + 6x + y -2z
= 2x + 4x + 6x + 3y + y - 4y + 3z + 2z - 2z
= 12x + 4y - 4y + 5z - 2z
= 12x + 3z units
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