Question

find the perimeter rectangle whose area is 500 and breadth is 20​

Answer 1

Given:

Area of rectangle = 500

l*b=500

Given: b=20

l*20=500

=> l=500/20

= 25

Now, perimeter= 2(l+b)

= 2(25+20)

= 2(45) = 90

Answer 2

Question :-

• Find the perimeter rectangle whose area is 500cm² and breadth is 20cm.

Given :-

• Area of Rectangle = 500cm²
• Breadth of Rectangle = 20cm

To Find :-

• What is the perimeter of Rectangle?

Solution :-

Firstly, we have to find the Length of the Rectangle then, we can easily find the Perimeter of the Rectangle.

$\qquad \quad {:} \longrightarrow \sf \boxed {\bf{Area \: of \: Rectangle \: = \: Length \: \times \: Breadth }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{500 \: = \: Length \: \times \: 20 }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{ \cancel \dfrac{500}{20} \: = \: Length \: }}$

$\qquad \quad {:} \longrightarrow \sf {\bf{ 25\: = \: Length \: }}$

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$\qquad \quad {:} \longrightarrow \sf \boxed {\bf{ Perimeter \: of \: Rectangle \: = \: 2(Length \: + \: Breadth) }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{ Perimeter \: of \: Rectangle \: = \: 2(25 \: + \: 20) }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{ Perimeter \: of \: Rectangle \: = \: 2\: \times \: 45 }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{ Perimeter \: of \: Rectangle \: = \: 90}}$

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$\begin{gathered}\begin{gathered}\therefore\: \sf{ Perimeter \: of \: Rectangle \: = \underline {\underline{ 90cm}}}\\\end{gathered}\end{gathered}$

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