Question

Find the perimeter whose length is 18m65cm and breadth is 12 m 15 cm

Answer 1

$\huge{\mathfrak{Hola\:mate}}$
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$\huge\sf{Answer}$

$length = 18m \: and \: 65m \\ = > (18 + \frac{65}{100} )m \\ = > (18 + 0.65)m \\ = > 18.65m$

$breadth \: = 12m \: and \: 15cm \\ = > (12 + \frac{15}{100} )m \\ = > (12 + 0.15)m \\ = > 12.15 m$

${\red{\boxed{perimeter \: of \: rectangle = 2(l + b)}}}$

$= > 2(18.65 + 12.15)m \\ = > 2(30.80)m \\ = > 61.6m$

${\green{\boxed{so \: the \: perimeter \: is \: 55.6m}}}$

Answer 2

Answer:

Step-by-step explanation:

Length = 18m 65cm = 1865 cm

Breadth = 12m 15cm = 1215 cm

Perimeter = 2*(L+B) = 2*(1865+1215) = 2*3080 = 6160 cm or 61.60 m