Math, asked by siyadubey16, 11 months ago

Find the perimeters of (i) the triangle ABE (ii) the rectangle BCDE in this figure. Whose perimeter is greater?


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Answers

Answered by Raja395
4

Step-by-step explanation:

AB = 5/2 cm = 2.5 cm

BE = 2 3/4 cm = 11/4 cm = 2.75 cm

AE = 3 3/5 cm = 18/5 cm = 3.6 cm

DE = 7/6 cm

Also, in rectangle BCDE,

CD = BE = 11/4 cm = 2.75 cm

BC = DE = 7/6 cm

(i) Perimeter of Triangle ABE = AB + BE + AE

= 2.5 cm + 2.75 cm + 3.6 cm

= 8.85 cm

(ii) Perimeter of rectangle BCDE = BC + CD + DE + BE

= 7/6 + 11/4 + 7/6 + 11/4

= (7*2 + 11*3 + 7*2 + 11*3)/12

= (14 + 33 + 14 + 33)/12

= 94/12

= 47/6 cm

Thanks!

Answered by Anonymous
1

Answer:

47/6 is your answer friend

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