Question

Find the perimeters of the following:
(a) A rectangle of length 16 cm and breadth 10 cm
(b) A parallelogram of length 21 cm and breadth 15 cm
(c) A triangle with sides measuring 10 cm, 14 cm and 16 cm​

Answer 1

Answer:

a 15

b.72

c.40

Step-by-step explanation:

Answer 2

$\underline \bold{Answer} \\ \\ (a) \: \: \: \: \: \: \: \: \: \: \: \: \: \: length = 16 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ breadth = 10 \: cm \\ \\ {\underline{\underline{\boxed{\sf{Perimeter \: of \: rectangle = length \times breadth)}}}}} \\ \\ \rightarrow \: (16 \times 10)cm \: \: \: \: \\ \rightarrow 160 {cm}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ (b) \: \: \: \: \: \: \: \: length \: of \: paralellogram = 21 \: cm \: \: \: \: \: \: \: \: \: \: \: \\ breadth \: of \: paralellogram = 15 \: cm \\ \\ {\underline{\underline{\boxed{\sf{Perimeter \: of \: paralellogram = sum \: of \: all \: the \: sides}}}}} \\ \rightarrow \: 21 + 21 + 15 + 15 \\ \rightarrow \: 72 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ (c) \: \: \: \: \: \: first \: side = 10 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ second \: side = 14 \: cm \\ third \: side = 16 \: cm \\ \\ {\underline{\underline{\boxed{\sf{Perimeter \: of \: triangle = sum \: of \: all \: sides}}}}} \\ \rightarrow \: 10 + 14 + 16 \: \: \: \: \: \: \: \: \: \\ \rightarrow \: 40 \: cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$