Find the perimeters of¡) triangle abc ¡¡) the rectangle bcde in this figure. which figure has greater perimetre and by how much?
Answers
Answer:
Sides of Δ ABE : -
3 \dfrac{1}{3}3
3
1
cm
2 \dfrac{1}{5}2
5
1
cm
4 \dfrac{2}{3}4
3
2
cm
Perimeter of ΔABE = sum of all sides
Perimeter of ΔABE = 3 \dfrac{1}{3}\: cm + 2 \dfrac{1}{5}\: cm +4 \dfrac{2}{3}3
3
1
cm+2
5
1
cm+4
3
2
cm
Perimeter of ΔABE = 10 / 3 cm + 11 / 5 cm + 14 / 3 cm
Perimeter of ΔABE = 50 / 15 + 33 / 15 + 70 / 15 cm
Perimeter of ΔABE = ( 50 + 33 + 70 ) / 15 cm
Perimeter of ΔABE = 153 / 15 cm
( ii ) :
Perimeter of rectangle = 2( length + breadth )
Perimeter of rectangle = 2( 2 \dfrac{1}{5}\:cm+ 1\dfrac{2}{3}2
5
1
cm+1
3
2
)
Perimeter of rectangle = 2( 11 / 5 cm + 5 / 3 cm )
Perimeter of rectangle = 2( 33 / 15 cm + 25 / 15 cm )
Perimeter of rectangle = 2( 58 / 15 )
Perimeter of rectangle = 116 / 15 cm
As 153 / 15 > 1116 / 15. Triangular figure has greater perimeter and by ( 153 - 116 ) / 15 ; 37 / 15