Question

Find the perimeters of triangle ABE and rectangle BCDE,whose sides of the tringle are AB=5/2cm,BE=2 3/4cm,EA=3 3/5cm And the sides of rectangle are BE and CD =2 3/4 and BC and DE=7/6cm

Answer 1

Answer:

perimeter of triangle is 9 2/20 cm

perimeter of rectangle is 7 5/6 cm

Step by step explanation :

perimeter of triangle = sum of all its sides

perimeter of triangle ABE = AB+BE+EA

=5/2+2 3/4+3 3/5

=5/2+11/4+18/5

=(50+55+72)/20

=182/20

=9 2/20 cm

perimeter of rectangle = 2(a+b)

=2(BC+CD)

=2(7/6+2 3/4)

=2(7/6+11/4)

=2((14+33)/12)

=2*47/12

=47/6

=7 5/6 cm