Question

Find the perimetre of a rectangular field whose lenght is 4 times its width and which has area equal to 20736sq. m.​

Answer 1

Answer:

AREA OF RECTANGLE=LENGTH*BREADTH

20736=4*width*width                 [given in ques that length=4*width]

width²=5184

width=72m

hence length=4*72=288m

now

perimeter=2[length+width]

perimeter=2[72+288]

perimeter=720m is answer

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Step-by-step explanation:

Answer 2

Answer:

Perimeter of a rectangular field is 720 m

Step-by-step explanation:

We know that, Perimeter of rectangle = 2(length +width)

By given conditions

Length = 4× width

Area of rectangle = length × width

20736 = 4× width × width

20736÷4 = (width)^2

5184 = ( width)^2

width = square root of 5184

width = 72.

therefore lenght = 4×72

= 288

Therefore, perimeter = 2( 288+72 )

= 720

Hence, perimeter of a rectangular field is 720 m.