Math, asked by happyraja82, 3 months ago

find the perimetre of trapezium ​

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Answers

Answered by manvithshetty69
0

Answer:

LEGENDS WILL SURELY LIKE THIS

Answered by DrNykterstein
7

Answer: 36 units

Refer to the attachment.

Given figure is trapezium hence there is not a particular formula for finding the perimeter cuz there are Non Isosceles trapeziums too.

According to the diagram, this is an Isosceles trapezium as its non parallel sides are equal.

Perimeter :- Some of all the sides that close up the figure (lines that act as boundary) excluding those sides which are inside the figure.

Here, Perimeter is given by:

⇒ Sum of the parallel sides + Sum of the non-parallel sides

We are given the measurement of the parallel sides and height of the trapezium but not the measurement of the non-parallel sides so let's find it.

Drop a perpendicular from the vertex C on the line segment AD at point F which will be equal in magnitude to BE i.e., 4 units.

After construction, we get a rectangular shaped figure BEFC. In a rectangle opposite sides are equal. Hence,

  • BC = EF = 10 units ...(i)

Now, we don't know the measurement of AE,

So let's find it out,

⇒ AD = 16 [ given ]

⇒ AE + EF + FD = 16

because, AE = FD, Because it is an isosceles trapezium.

⇒ AE + EF + AE = 16

⇒ 2AE + 10 = 16 [ EF = 10 units, eq.(i) ]

⇒ 2AE = 6

AE = 3

Now that, we have AE = 3 & BE = 4 (given),

In ∆ABE by Pythagoras theorem,

⇒ AB² = AE² + BE²

⇒ AB² = (3)² + (4)²

⇒ AB² = 25

AB = 5 units [ AE = -5 , neglected as length can't be negative. ]

Also,

  • AB = CD = 5 units ...(ii)

[ Isosceles trapezium ]

As discussed earlier, Perimeter is given by,

⇒ Sum of parallel sides + Sum of non parallel sides

⇒ BC + AD + AB + CD

⇒ 10 + 16 + 5 + 5 [ AB=CD=5units, See eq.(ii) ]

⇒ 26 + 10

36 units

Hence, Perimeter of the given trapezium is 36 units.

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