Question

Find the perimetwr of the rectangle whose length is 10 1/2cm and breadth is 4 1/4cm

Answer 1

perimeter =2 (l+b)
=2 (21/2+17/4)
=2 (42/4+17/4)
=2 (42 +17)÷4
=69/2
=34 1/2


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Answer 2

$peimeter \: of \: a \: rectngle \\ = 2(a + b) \\ \\ here \: a = 10 \times \frac{1}{2} cm \\ b = 4 \times \frac{1}{4} cm \\ \\ perimeter \: = 2( \frac{21}{2} + \frac{17}{4} ) \\ = 2( \frac{42 + 17}{4} ) \\ = \frac{59}{2}$
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