Math, asked by rgindustries06, 8 months ago

find the perimter and area of the following figures​

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Answers

Answered by arush8306
0

area of rectangle=l×b

=10×7

=70m^2

perimeter of rectangle=2(l+b)

2(10+7)

2(17)

2×17

=34

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Answered by kpr2007
0

area \: is \:  =  \: l \times b = 10 \times 7 = 70 {m}^{2}

perimeter \: is \:  =  \: 2(l + b) = 2(7 + 10) = 2(17) = 34m

area \: of \: semicircle \: is \:  =  \frac{\pi  {r}^{2} }{2}  =  \frac{22 \times  3.5\times 3.5}{7 \times 2}  = 11 \times 0.5 \times 3.5 = 19.25{cm}^{2}

perimeter \: of \: semicircle \: is \:  = \pi  r + d =  \frac{22}{7}  \times 3.5 + 7 = 22 \times 0.5  + 7 = 11 + 7 = 18cm

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