Find the period for the function: 2 sin ( + x) cos x
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we know, if T is the period of function y = f(x) and R is the period of function, y = g(x) then period of y = f(x) ± g(x) will be LCM{T,R}
and also, if T is the period of function, y = f(x) then, T/|a| is the period of function, y = f(ax ± b)
now, f(x) = 2sin(π/4 + x)cosx
use formula, 2sinA.cosB = sin(A + B) + sin(A - B)
so, f(x) = sin(π/4 + x + x) + sin(π/4 + x - x)
f(x) = sin(2x + π/4) + sin(π/4)
f(x) = sin(2x + π/4) + 1/√2
we know, period of sinx = 2π
so, period of sin(2x + π/4) = 2π/2 = π
hence, period of function, f(x) = sin(2x + π/4) + 1/√2 is π
therefore, period of 2sin(π/4 + x)cosx is π
and also, if T is the period of function, y = f(x) then, T/|a| is the period of function, y = f(ax ± b)
now, f(x) = 2sin(π/4 + x)cosx
use formula, 2sinA.cosB = sin(A + B) + sin(A - B)
so, f(x) = sin(π/4 + x + x) + sin(π/4 + x - x)
f(x) = sin(2x + π/4) + sin(π/4)
f(x) = sin(2x + π/4) + 1/√2
we know, period of sinx = 2π
so, period of sin(2x + π/4) = 2π/2 = π
hence, period of function, f(x) = sin(2x + π/4) + 1/√2 is π
therefore, period of 2sin(π/4 + x)cosx is π
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