Math, asked by NoobPeen, 1 year ago

Find the period of (2sinX+3cosX/2)/4tan2X-7sin3X

Answers

Answered by kavinhaasan4

8

Answer:

Step-by-step explanation:

=(2sinx+3cosx/2)/4tan2x-7sin3x

=period=lcm of the numerator/hcf of the denominator

=(lcm of 2pi and 4pi)/(hcf of pi/2,2pi/3)

=4pi/1

=4pi

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