Question

find the period of function tan (x+4x+9x+...+n²)x​

Answer 1

Answer:

Answer is 3π/n(n+1)(2n+1)

Step-by-step explanation:

If the period of a function f(x) is T, then the period of f(ax) is T/|a|.

Tan(1+2^2 + 3^2+…....n^2) = π/2{(n)(n+1)(2n+1)÷6} = 3π/n(n+1)(2n+1) is period of tanx is π/2.

Hope it helps you ...!!