Question

Find the permeter of a rectangle whose area 8 2/3 sq.mm, length 5 7/9mm

Answer 1

Step-by-step explanation:

hi Clara

here is ur answer

area of rectangle =l×b

area =8×2/3 sqmm

length= 5×7/9mm

breadth =?

26/3= 52/9×b

b= 26/3×9/52

b= 78/52

so now we can find perimeter of rectangle

perimeter of the rectangle = 2(l+b)

=> 2(52/9+78/52)

=> 2( 1703/234)

=>3406/234

so the perimeter of the rectangle is 3406/234