Question

Find the permitivity of free space ?​

Answer 1

Explanation:

From F=4πεo1r2q2

If Force, F=1N

charge, q=1C

distance, r=1m

Then, qo=F×4π×r2q2

=1N×4×3.14×(1m)2(1)2

εo=8.854×10−12Nm2C2

Answer 2

Answer:

The Permittivity of Free Space ε0=8.85∗10−12 ε 0 = 8.85 ∗ 10 − 12 Farad/meter.

Explanation:

It is the property of every material, which measures the opposition offered against the formation of an electric field. Represented by the Greek alphabet ϵ. It tells the number of charges required to generate one unit of electric flux in the given medium