find the perpendicular components of a force of 50 N making an angle of 30with x axis
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Explanation:
Forces are vectors and so can obey the standard geometric rules (assuming we have a simple spacetime and geometry)
Fx=F0cos θ
Fy=F0sin θ
Here F0=10N and θ=30∘
You can convince yourself of this because if the angle of the slope was 0, the x force would be 10 and the y force would be 0 which makes sense.
So in this case,
Fx=10cos30∘≈8.66N
Fy=10sin30∘=5N
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