Math, asked by Vikuu7815, 1 year ago

Find the perpendicular distance between two parallel lines of a trapezium whose parallel sides are 30cm and 24cm and area is 405cm²

Answers

Answered by Anonymous
12
i hope you help. ....
Attachments:
Answered by wifilethbridge
9

The perpendicular distance between two parallel lines of a trapezium are 15 cm

Step-by-step explanation:

Length of parallel sides are 30cm and 24cm

Let the height be h

Area of trap.=\frac{1}{2}(\text{Sum of parallel sides}) \times height

Area of trap.=\frac{1}{2}(30+24)\times Height

We are given that area is 405cm²

So, \frac{1}{2}(30+24) \times Height = 405

Height = \frac{405 \times 2}{30+24}

Height =15

Hence the perpendicular distance between two parallel lines of a trapezium are 15 cm

#Learn more:

Find the area of a trapezium whose parallel sides are 24cm and 20cm and the distance between them is 15cm

https://brainly.in/question/2050057

Similar questions