Question

find the perpendicular distance from a point (2,-3) to the line 5x+12y+13=0

Answer 1

Given:

point (2,-3) and the line 5x+12y+13=0.

To find:

perpendicular distance from the point and the line.

Solution:

1) To find the perpendicular distance between the point and the line.

2) There is the direct formula to find the perpendicular distance between the point and the line.

• $d=|Ax+By+C|/\sqrt{x^{2}+y^{2}}$

3) 5x+12y+13=0 on comparing with we get

• A=5

• B=12

• C=13

• x=2

• y= -3

4) Put all the values of the variables in the formula.

• $d=|5*2+12* -3+13|/\sqrt{2^{2}+(-3)^{2}}$

• d= 13/√13

• d = √13

Perpendicular distance from the point and the line is √13 approx 3.606 .

Answer 2

the perpendicular distance from a point (2,-3) to the line 5x+12y+13=0 is 1