find.the perpendicular distance from the point (2,-3) from the line 2x-3y-25=0
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Distance of a point from a straight line means the perpendicular distance of the point from the line.
We are given the line x-y=5. Any line which is perpendicular to this line should be of the form x+y=c where c is the intercept of the line on the y-axis.
Now, in order to calculate the perpendicular distance from the point (-2,3) to the line, the line x+y=c should pass through (-2,3). So the perpendicular line is x+y=1 and it intersects the line x-y=5 at the point (3,-2).
Required distance is the distance between the points (-2,3) and (3,-2) which is 5√2 units.
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