find the perpendicular distance from the point P(x1,y1) to the line Ax+By+C=0
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The perpendicular distance from the point to line is given by
|A(x1) + B(y1) +C|/sqrt(A^2+B^2)
|A(x1) + B(y1) +C|/sqrt(A^2+B^2)
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Answer:
|Ax1+By1+C|/√A²+B² is the answer
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