Question

find the perpendicular distance of point (3,1) from y-axis​

Answer 1

the point is (0, 1) is exactly perpendicular to the point(3, 1)

the distance between these two points is..√[3^2+(1-1)^2]

.... =√9

= 3 units

Answer 2

The perpendicular distance of point (3,1) from y-axis​ is 3 units.

Explanation:

For any point having coordinates (a,b) , as this point is perpendicular to both axis (at x= a on x-axis and on y= b on y-axis)

The perpendicular distance of the point from x axis is b units.

The perpendicular distance of the point from y axis is a units.

Similarly , the perpendicular distance of point (3,1) from y-axis​ would be  3 units.

Or we can check the graph , The line drawn from (3,1) is perpendicular to y-axis at (0,1).

By distance formula , distance =$|x_2-x_1| =|3-0|=3$  (∵ y-coordinate remained same.)

Hence, the perpendicular distance of point (3,1) from y-axis​ is 3 units.

# Learn more :

If A is a point on Y axis,whose ordinate is 4 and coordinate of point B is (-3,1).then find the distance AB

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