Question

find the perpendicular distance of point A(3,-7) from x-axis.
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Answer 1

Answer:

The perpendicular distance is 7 units.

Answer 2

Given:

A(3,-7)

To find:

The perpendicular distance of A from the x-axis

Solution:

The required distance is 7 units.

We know that the point's coordinates on the x-axis will have the same abscissa and 0 as its ordinate.

So, let the point touching the x-axis be B.

The coordinates of B=(3, 0)

Now, the required distance between A and B can be obtained as follows-

Distance required=$\sqrt{ (y2-y1)^{2} +(x2-x1)^{2} }$

(x1, y1)=(3, -7)

(x2, y2)=(3, 0)

Using the values,

=$\sqrt{(0-(-7))^{2}+ (3-3)^{2} }$

=$\sqrt{7^{2} }$

=7 units

Therefore, the required distance is 7 units.