Question

find the perpendicular distance of the moment of force 40 N about a point is 5 N m​

Answer 1

Answer:

Solution:

Force applied = 25 N

\bot⊥ distance from the point of rotation = ?

Moment of force = Force \times× \bot⊥ distance

2.5 = 25 \times× \bot⊥ distance

distance = 2.5/25 = 1/10 m = 10 cm

Answer 2

Step-by-step explanation:

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.

5=r×10

r=0.5m.

Hence we apply a force at a perpendicular distance of 0.5 m.

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