Question

find the perpendicular distance of the point (0,0) to the line 3x-4y-20=0​

Answer 1

Answer:

4

Step-by-step explanation:

As we know that the distance of the point (x1,y1,z1) from ax+by+cz+d=0 is given as-

d=a2+b2+c2∣ax1+by1+cz1+d∣

Given that the point is (0,0,−7) and the plane is 3x+4y−20=0

Therefore,

d=(3)2+(4)2∣3(0)+4(0)−20∣=25∣−20∣=520=4

Hence the distance between the point and the plane is 4 units.