Question

Find the perpendicular distance of the point (1,2) from the line 3x+4y-13=0

Answer 1

Step-by-step explanation:

As you mention, points (-3,-4) to the line

3x-4y-1=0,

• let x=-3 and y=-4

• So comparing the line with equation

• Ax+By+C=0

• A=3, B=-4 and C=-1

Equation for distance between line and coordinate axes pts. Is

• d=|Ax+By+C|(√A2+B2)

∙d=|3(−3)−4(−4)−1|(√9+16)

∙d=6/5