Question

find the perpendicular distance of the point (2,-3) from the line 2x-3y-25=0​

Answer 1

Answer

2(2)-3(-3)-25=0

4+9-25=0

13-25=0

-12=0

=0-12

12

Answer 2

Answer:

we know that,

the perpendicular distance from P(x1,y1) to the line ax+by+c=0 is |ax1+by1+c|/√(a^2+b^2)

therefore,

12/√13 is the answer

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