Question

Find the perpendicular distance of the point p(4,2) from the y-axis

Answer 1

Perpendicular distance of the point p ( 4,2) from the y-axis is equal to its x coordinate.

Therefore it is 2 units

 

Answer 2

Answer:

The perpendicular distance of the point p(4,2) from the y-axis is 4

Step-by-step explanation:

The equation of the y axis is x =0

Given point is p(4,2)

Now, the formula for the perpendicular distance of a point (p.q) from the line ax+by+c=0 is

$d=\frac{ap+bq+c}{\sqrt{a^2+b^2}}$

Substituting the known values a=1,b=0,c=0,p=4,q=2

$d=\frac{1\cdot4+0+0}{\sqrt{1^2+0^2}}\\\\\d=\frac{4}{1}\\\\d=4$

Therefore, the perpendicular distance of the point p(4,2) from the y-axis is 4