Question

Find the perpendicular distance of the point p(5 7) from the y axis

Answer 1

jhkg+23+65+65+65+6566+65

Answer 2

Answer:

5 units

Step-by-step explanation:

The point on y axis which is perpendicular to p(5,7) would be (0,7)

By using distance formula,

$\sqrt{(x1 - x2)^{2} + (y1 - y2)^{2}}$

$\sqrt{(5-0)^{2} + (7-7)^{2}}$

$\sqrt{(5)^{2} + (0)^{2}}$

$\sqrt{(5)^{2}}$

5 units

Hope this helps

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