Question

find the perpendicular of a right angle triangle if it base=6cm and hypothenuse =10​

Answer 1

Answer:

8cm

Step-by-step explanation:

perpendicular=√h²-b²

p=√[(10)²-(6)²]cm

p=√(100-36)cm

p=√64cm

p=8cm

hope it helps you

Answer 2

By the Pythagoras Theorem,

h² = b² + p²

Hence,

$\huge \frak{ {(10)}^{2} = {(6)}^{2} + {p}^{2} } \\ \huge \frak{ \: \: {(p)}^{2} = {(10)}^{2} - {(6)}^{2} } \\ \\ { \large \frak{ \: \: = > {p}^{2} = (10 - 6)(10 + 6)}} \\ \large \frak{ \: \: = > {p}^{2} = 4 \times 16 } \\ \large \frak{ \: \: = > p = \sqrt{4 \times 16} } \\ \large \frak{ \: \: = > p = \sqrt{64} = 8 \: cm}$

Thus, Perpendicular of the given triangle is 8 cm.

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