Question

Find
the
perpendiculas distance
of the
point
(2, 3)
from
the
line
2x-y-320,​

Answer 1

Answer

Find the distance of the point (2,3) form the line 2x−3y+9=0 measurement along a line x−y+1=0.

Easy

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Answer

2x−3y+9=0 ……..(i),

x−y+1=0 ………(ii)

Multiply equation (ii) by 2 and subtract it from equation (1)

2x−3y+9=0

2x−2y+2=0

_____________

−y+7=0

_____________

y=7,x=6

Point of intersection (6,7)

Distance between (2,3) and (6,7)=

(6−2)

2

+(7−3)

2

=4

2

units

∴ Distance of the point (2,3) from the line 2x−3y+9=0 measured along line x−y+1=0 is 4

2

units.

solution

Expand-image

Answer 2

Step-by-step explanation:

تربیت کے ، فنی اور معاشرتی لحاظ سے کیا فوائد ہیں ؟