Find the pH of 10^-3 M HCl
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Answer:
HCl is a strong electrolyte and is completely ionised
HCl⇌H
+
+Cl
−
So, [H
+
]=10
−3
M
pH=−log[H
+
]=−log10
−3
=3
(b) NaOH is a strong electrolyte and is completely ionised
NaOH⇌Na
+
+OH
−
so, [OH
+
]=0.0001M=10
−4
M
pOH=−log10
−4
=4
(c) H
2
SO
4
is a strong electrolyte and is completely ionised
H
2
SO
4
⇌2H
+
+SO
4
2−
One molecule of H
2
SO
4
furnishes 2H
+
ions
So, [H
+
]=2×10
−4
M
pH=−log[H
+
]
=3.70
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