Chemistry, asked by chattarajdebanjan01, 5 months ago

Find the pH of M/10 HCOONH4 ( Ka(HCOOH) = 10^-4 , Kb ( NH4OH) = 10^-5

Answers

Answered by SuperstarGold

1

Answer: 7+(1/2)×3.8−(1/2)×4.8=7+1.9−2.4=6.5

Explanation:

pK

a

=3.8, pK

b

=4.8

pH=7+

2

1

pK

a

−

2

1

pK

b

=7+(1/2)×3.8−(1/2)×4.8=7+1.9−2.4=6.5

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