find the pH value of NaoH solution in which h+ ion concentration is 10^-11 m.
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Answer:
11
Explanation:
ph = -log [H+] (Note:- log is to the base 10)
where [H+] is the H+ ion concentration
H+ ion concentration = 10^-11 M
ph = -log [10^-11] = -(-11 log[10]) = -(-11) = 11
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