Question

Find the phathagors triplet whose one member is 22

Answer 1

Step-by-step explanation:

$we \: know \: that \: formula \: for \: \\ Pythagorean \: triplet \: is \\ (2m \: \: and \: {m}^{2} - 1 \: and \: {m}^{2} - 1) \\ so \: now \: let \: \\ 2m = 22 \\ = > m = 11 \\ now \: {m}^{2} - 1 = {11}^{2} - 1 \\ = 121 - 1 \\ = 120 \\ now \: {m}^{2} + 1 = {11}^{2} + 1 = 122 \\ thus \: the \: required \: pythagorean \: \\ is \: 22 \:and \: 120 \: and \: 122 \\ om \: namah \: shivaya \\ debasish \: biswal$