Find the phenotypic and genotypic ratio of a cross between pea plants with genotype rrTt and Rrtt
using a Punnet square.
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Explanation:
The second parent with genotype"Rrtt" will form Rt and rt gametes. Random fusion of gametes from two parents produces four genotypes ttRr (dwarf, round), TtRr (tall, round), ttrr (dwarf, wrinkled) and Ttrr (tall, wrinkled) in 1:1:1:1 ratio. So, the obtained phenotypic ratio will be 1:1:1:1. The correct answer is B.
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