Question

find the phythogorean triplet whose largest number 10

Answer 1

take the square of 10(10^2=100)
divide it by 2 (100/2=50)
(I)add 2 to 50 (50+2=52)
(ii)subtract 2 by 50(50-2=48)
divide them by 2
(I)52/2=26
(ii)48/2=24
10,24,26are triple (10^2+24^2=26^2)
and because 3,4,5 are a triple their double must also be so 6,8,10are also triple (6^2+8^2=10^2)