find the phythogorean triplet whose largest number 10
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take the square of 10 (10^2=100)
divide it by 2 (100/2=50)
i)add 2 to 50(50+2=52) ii)subtract 2 by 50(50–2=48)
divide them by 2;
i)52/2=26 ii)48/2=24
10,24,26 are the triple (10^2+24^2=26^2)
and because 3,4,5 are a triple their double must also be so 6,8,10 are also a triple(6^2+8^2=10^2)
divide it by 2 (100/2=50)
i)add 2 to 50(50+2=52) ii)subtract 2 by 50(50–2=48)
divide them by 2;
i)52/2=26 ii)48/2=24
10,24,26 are the triple (10^2+24^2=26^2)
and because 3,4,5 are a triple their double must also be so 6,8,10 are also a triple(6^2+8^2=10^2)
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answer is
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