Math, asked by omesh1624, 8 months ago

Find the pithagoras triplet whose smallest number is 22

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Answered by sk6154015

0

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Answered by YashiShingla

1

Answer:

2m=22

m=22÷2=11

m²+1=11²+1=121+1=122

m²-1=11²-1=121-1=120

Hence the required triplets are 22,122,120

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