Question

Find the point A(x,y) when C divides AB in the ratio 2:3.Points B and C are given as (-5,8) and (3,6)

Answer 1

Given :  C divides AB in the ratio 2:3.Points B and C are given as (-5,8) and (3,6)

To Find : point A(x,y)

Solution:

A  (x,y)

B   (-5,8)

C  (3,6)

C divides AB  in 2:3 ratio

=> Cx = (2Bx + 3Ax)/(2 + 3)

  Cy = (2By + 3Ay)/(2 + 3)  

Cx = (2Bx + 3Ax)/(2 + 3)

=> 3  = ( 2 *(-5) + 3x) /5

=>15 = -10  + 3x

=> 3x = 25

=> x = 25/3

 Cy = (2By + 3Ay)/(2 + 3)  

=> 6  = ( 2 *8 + 3y) /5

=>30 = 16  + 3y

=> 3y = 14

=> y = 14/3

point A(x,y)  = ( 25/3 , 14/3)

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Answer 2

Answer:

So the points are 25/3,14/3

Step-by-step explanation:

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